Solution
Solution
Solution steps
Apply Series Ratio Test:converges
Popular Examples
sum from n=3 to infinity of 1/(n(n-2))sum from n=5 to infinity of 1/(n^2ln(n))sum from n=1 to infinity of ((n+2)/n)^nsum from n=1 to infinity of 7/(n^{2/5)}sum from n=1 to infinity of (6n)/(3n+9)
Frequently Asked Questions (FAQ)
What is the sum from n=0 to infinity of 1/(6^n-5) ?
The sum from n=0 to infinity of 1/(6^n-5) is converges