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Popular >

derivative of 2(x^2+y^2^2)

Solution

\frac{d}{d x} (2 (x^{2} + y^{2})^{2})

Solution

4 (x^{2} + y^{2}) (2 x + 2 y \frac{d y}{d x})

Solution steps

\frac{d}{d x} (2 (x^{2} + y^{2})^{2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} ((x^{2} + y^{2})^{2})

Apply the chain rule:

2 (x^{2} + y^{2}) \frac{d}{d x} (x^{2} + y^{2})

= 2 (x^{2} + y^{2}) \frac{d}{d x} (x^{2} + y^{2})

\frac{d}{d x} (x^{2} + y^{2}) = 2 x + 2 y \frac{d y}{d x}

= 2 \cdot 2 (x^{2} + y^{2}) (2 x + 2 y \frac{d y}{d x})

Simplify

= 4 (x^{2} + y^{2}) (2 x + 2 y \frac{d y}{d x})

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\int cos (3 x) cos (9 x) d x

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\int \frac{2 x - 2}{x ^{2} - 2 x} d x

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\frac{1}{s} \frac{1}{s ^{2} + 20 s + 100}

integral from 0 to 3 of-2x^2

\int_{0}^{3} - 2 x^{2} d x

(\partial)/(\partial y)(3y^2x^4)

\frac{\partial}{\partial y} (3 y^{2} x^{4})

Frequently Asked Questions (FAQ)

What is the derivative of 2(x^2+y^2^2) ?
The derivative of 2(x^2+y^2^2) is 4(x^2+y^2)(2x+2y(dy)/(dx))
What is the first derivative of 2(x^2+y^2^2) ?
The first derivative of 2(x^2+y^2^2) is 4(x^2+y^2)(2x+2y(dy)/(dx))