What is the sum from n=1 to infinity of 1/(n^{25)} ?

The sum from n=1 to infinity of 1/(n^{25)} is converges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sum from n=1 to infinity of 1/(n^{25)}

n = 1 \sum \infty \frac{1}{n ^{25}}

converges

Solution steps

n = 1 \sum \infty \frac{1}{n ^{25}}

Apply p-Series Test:

converges

= converges

n = 1 \sum \infty \frac{n !}{3 n ! + 1}

n = 1 \sum \infty 4 (- \frac{10}{11})^{n}

k = 1 \sum \infty \frac{k}{e ^{4 k}}

n = 0 \sum \infty (\frac{4}{3})^{n}

n = 5 \sum \infty \frac{1}{n ^{2} - 5 n + 6}

What is the sum from n=1 to infinity of 1/(n^{25)} ?
The sum from n=1 to infinity of 1/(n^{25)} is converges