What is the sum from n=1 to infinity of (7^n)/n ?

The sum from n=1 to infinity of (7^n)/n is diverges

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sum from n=1 to infinity of (7^n)/n

n = 1 \sum \infty \frac{7 ^{n}}{n}

diverges

Solution steps

n = 1 \sum \infty \frac{7 ^{n}}{n}

Apply Series Ratio Test:

diverges

= diverges

n = 1 \sum \infty [1 + (- 1)^{n}]

n = 1 \sum \infty \frac{4}{n ln ( n )}

n = 1 \sum \infty \frac{2}{n + 2}

n = 1 \sum \infty \frac{5}{3 n ^{2}}

n = 1 \sum \infty \frac{1}{2 \cdot n - 1}

What is the sum from n=1 to infinity of (7^n)/n ?
The sum from n=1 to infinity of (7^n)/n is diverges