What is the solution for (dy)/(dx)y=(2x+8)^3 ?

The solution for (dy)/(dx)y=(2x+8)^3 is y=sqrt(1/4 (2x+8)^4+c_{1)},y=-sqrt(1/4 (2x+8)^4+c_{1)}

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(dy)/(dx)y=(2x+8)^3

\frac{d y}{d x} y = (2 x + 8)^{3}

y = \frac{1}{4} (2 x + 8)^{4} + c_{1}, y = - \frac{1}{4} (2 x + 8)^{4} + c_{1}

Solution steps

\frac{d y}{d x} y = (2 x + 8)^{3}

Solve separable ODE:

y = \frac{1}{4} (2 x + 8)^{4} + c_{1}, y = - \frac{1}{4} (2 x + 8)^{4} + c_{1}

y = \frac{1}{4} (2 x + 8)^{4} + c_{1}, y = - \frac{1}{4} (2 x + 8)^{4} + c_{1}

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What is the solution for (dy)/(dx)y=(2x+8)^3 ?
The solution for (dy)/(dx)y=(2x+8)^3 is y=sqrt(1/4 (2x+8)^4+c_{1)},y=-sqrt(1/4 (2x+8)^4+c_{1)}