Solution

Solution

Solution steps
Apply Series Ratio Test:converges

Popular Examples

sum from n=3 to infinity of 4(1/2)^{n+2}sum from n=1 to infinity of (1+n^2)/(n!)sum from n=1 to infinity of 5n^2e^{-n^3}sum from n=1 to infinity of ne^{-4n^2}sum from n=1 to infinity of (n!)/(5+n)

Frequently Asked Questions (FAQ)

  • What is the sum from n=1 to infinity of 3^{-3n} ?

    The sum from n=1 to infinity of 3^{-3n} is converges