What is the sum from n=0 to infinity of n/(6n+1) ?

The sum from n=0 to infinity of n/(6n+1) is diverges

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sum from n=0 to infinity of n/(6n+1)

n = 0 \sum \infty \frac{n}{6 n + 1}

diverges

Solution steps

n = 0 \sum \infty \frac{n}{6 n + 1}

Apply Series Divergence Test:

diverges

= diverges

n = 1 \sum \infty \frac{1}{3 n ^{5} + 4}

n = 0 \sum \infty \frac{i ^{2 n}}{3 n}

n = 1 \sum \infty - n^{- \frac{1}{2}}

n = 1 \sum \infty \frac{4}{n ^{2} + 2 n}

n = 1 \sum \infty \frac{1}{( n ( n + 1 ) )}

What is the sum from n=0 to infinity of n/(6n+1) ?
The sum from n=0 to infinity of n/(6n+1) is diverges