What is the derivative of e^{-x}+e^{-2x} ?

The derivative of e^{-x}+e^{-2x} is -e^{-x}-2e^{-2x}

What is the first derivative of e^{-x}+e^{-2x} ?

The first derivative of e^{-x}+e^{-2x} is -e^{-x}-2e^{-2x}

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\frac{d}{d x} (e^{- x} + e^{- 2 x})

- e^{- x} - 2 e^{- 2 x}

Solution steps

\frac{d}{d x} (e^{- x} + e^{- 2 x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (e^{- x}) + \frac{d}{d x} (e^{- 2 x})

\frac{d}{d x} (e^{- x}) = - e^{- x}

\frac{d}{d x} (e^{- 2 x}) = - 2 e^{- 2 x}

= - e^{- x} - 2 e^{- 2 x}

\frac{\partial}{\partial x} (2 e^{x})

x y^{^{'}} + y = 2 x y^{2}

\frac{d}{d x} (2^{2 x + 2})

\int \frac{x ( 3 - 5 x )}{( 3 x - 1 ) ( x - 1 ) ^{2}} d x

x \to 3 - lim (\frac{1}{( x - 3 ) ^{3}})

What is the derivative of e^{-x}+e^{-2x} ?
The derivative of e^{-x}+e^{-2x} is -e^{-x}-2e^{-2x}
What is the first derivative of e^{-x}+e^{-2x} ?
The first derivative of e^{-x}+e^{-2x} is -e^{-x}-2e^{-2x}