What is the sum from n=0 to infinity of ((-4)^n)/n ?

The sum from n=0 to infinity of ((-4)^n)/n is diverges

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sum from n=0 to infinity of ((-4)^n)/n

n = 0 \sum \infty \frac{( - 4 ) ^{n}}{n}

diverges

Solution steps

n = 1 \sum \infty \frac{( - 4 ) ^{n}}{n}

Apply Series Ratio Test:

diverges

= diverges

n = 0 \sum \infty \frac{1}{5 ^{n} - 4 ^{n}}

n = 1 \sum \infty (cos (10))^{n}

n = 1 \sum \infty 7 n^{2} e^{- n^{3}}

n = 1 \sum \infty (- 1)^{n} sec (n)

n = 1 \sum \infty \frac{1}{12 n + 11}

What is the sum from n=0 to infinity of ((-4)^n)/n ?
The sum from n=0 to infinity of ((-4)^n)/n is diverges