What is the sum from n=0 to infinity of (4^n)/n ?

The sum from n=0 to infinity of (4^n)/n is diverges

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sum from n=0 to infinity of (4^n)/n

n = 0 \sum \infty \frac{4 ^{n}}{n}

diverges

Solution steps

n = 1 \sum \infty \frac{4 ^{n}}{n}

Apply Series Ratio Test:

diverges

= diverges

n = 0 \sum \infty 4 - \frac{1}{n}

n = 3 \sum \infty \frac{1}{8 e ^{2 n}}

n = 1 \sum \infty (\frac{1}{7})^{n - 1}

n = 0 \sum \infty \frac{( 0.5 ) ^{n}}{n}

n = 1 \sum \infty 4 (0.9)^{n - 1}

What is the sum from n=0 to infinity of (4^n)/n ?
The sum from n=0 to infinity of (4^n)/n is diverges