What is (\partial)/(\partial y)(2y^2) ?

The answer to (\partial)/(\partial y)(2y^2) is 4y

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(\partial)/(\partial y)(2y^2)

\frac{\partial}{\partial y} (2 y^{2})

4 y

Solution steps

\frac{\partial}{\partial y} (2 y^{2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{\partial}{\partial y} (y^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 2 \cdot 2 y^{2 - 1}

Simplify

= 4 y

x \to \infty + lim (i x)

\int_{0}^{\frac{π}{2}} 1

\frac{d}{d x} (\frac{2}{x + 8})

\frac{\partial}{\partial x} (3 - \frac{x}{3} - \frac{y}{2})

f (x) = - \frac{x ^{2}}{2} - 4 x - 10

What is (\partial)/(\partial y)(2y^2) ?
The answer to (\partial)/(\partial y)(2y^2) is 4y