What is the sum from n=0 to infinity of 2^n+i ?

The sum from n=0 to infinity of 2^n+i is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sum from n=0 to infinity of 2^n+i

n = 0 \sum \infty 2^{n} + i

diverges

Solution steps

n = 0 \sum \infty 2^{n} + i

Apply Series Divergence Test:

diverges

= diverges

n = 1 \sum \infty \frac{1}{ln ( 2 ^{n} )}

n = 1 \sum \infty \frac{3}{9 ^{n + 1}}

n = 1 \sum \infty 2 n + 3

n = 1 \sum \infty \frac{1}{8 n - 1}

n = 1 \sum \infty (\frac{1}{n})^{2}

What is the sum from n=0 to infinity of 2^n+i ?
The sum from n=0 to infinity of 2^n+i is diverges