What is the derivative of 2x^2+4x+3 ?

The derivative of 2x^2+4x+3 is 4x+4

What is the first derivative of 2x^2+4x+3 ?

The first derivative of 2x^2+4x+3 is 4x+4

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\frac{d}{d x} (2 x^{2} + 4 x + 3)

4 x + 4

Solution steps

\frac{d}{d x} (2 x^{2} + 4 x + 3)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{2}) + \frac{d}{d x} (4 x) + \frac{d}{d x} (3)

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (3) = 0

= 4 x + 4 + 0

Simplify

= 4 x + 4

\int \frac{x - 1}{( x ^{2} + 4 x + 5 ) ^{2}} d x

x \to \infty lim (\frac{- 2}{x})

\int \frac{1}{x 81 - x ^{2}} d x

\int 4 sin^{2} (5 x + 3) + 10 x^{\frac{2}{3}} - 1 d x

\frac{d}{d x} (\frac{x + 1}{3 x + 2})

What is the derivative of 2x^2+4x+3 ?
The derivative of 2x^2+4x+3 is 4x+4
What is the first derivative of 2x^2+4x+3 ?
The first derivative of 2x^2+4x+3 is 4x+4