What is the sum from n=1 to infinity of (2^n)/(n^4) ?

The sum from n=1 to infinity of (2^n)/(n^4) is diverges

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sum from n=1 to infinity of (2^n)/(n^4)

n = 1 \sum \infty \frac{2 ^{n}}{n ^{4}}

diverges

Solution steps

n = 1 \sum \infty \frac{2 ^{n}}{n ^{4}}

Apply Series Ratio Test:

diverges

= diverges

n = 0 \sum \infty \frac{1}{n ^{2} - n}

n = 1 \sum \infty \frac{7}{5 ^{n}}

n = 1 \sum \infty \frac{1 ^{n}}{n !}

n = 1 \sum \infty \frac{1}{4 n ^{2} - 25}

m = 2 \sum \infty \frac{2}{7 ^{m}}

What is the sum from n=1 to infinity of (2^n)/(n^4) ?
The sum from n=1 to infinity of (2^n)/(n^4) is diverges