What is (\partial)/(\partial x)(cos(x-y)-xe^y) ?

The answer to (\partial)/(\partial x)(cos(x-y)-xe^y) is -sin(x-y)-e^y

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(\partial)/(\partial x)(cos(x-y)-xe^y)

\frac{\partial}{\partial x} (cos (x - y) - x e^{y})

- sin (x - y) - e^{y}

Solution steps

\frac{\partial}{\partial x} (cos (x - y) - x e^{y})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (cos (x - y)) - \frac{\partial}{\partial x} (x e^{y})

\frac{\partial}{\partial x} (cos (x - y)) = - sin (x - y)

\frac{\partial}{\partial x} (x e^{y}) = e^{y}

= - sin (x - y) - e^{y}

f (x) = 3 x - x^{2}

x \to 1 lim (\frac{1}{x - 2})

f (x) = 9 (5^{x})

f (x) = c x^{- 6}

\frac{4}{s ^{2}}

What is (\partial)/(\partial x)(cos(x-y)-xe^y) ?
The answer to (\partial)/(\partial x)(cos(x-y)-xe^y) is -sin(x-y)-e^y