What is the sum from n=0 to infinity of (0.6)^n ?

The sum from n=0 to infinity of (0.6)^n is 2.5

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sum from n=0 to infinity of (0.6)^n

n = 0 \sum \infty (0.6)^{n}

2.5

Solution steps

n = 0 \sum \infty 0. 6^{n}

Apply Series Geometric Test:

2.5

= 2.5

n = 1 \sum \infty \frac{9}{e ^{n}}

n = 1 \sum \infty \frac{8 n}{5 n + 1}

k = 1 \sum \infty 2 (- \frac{1}{5})^{2 k}

n = 1 \sum \infty n^{- \frac{5}{2}}

k = 1 \sum \infty sin (\frac{1}{k})

What is the sum from n=0 to infinity of (0.6)^n ?
The sum from n=0 to infinity of (0.6)^n is 2.5