What is the derivative of (x^2+1/(x-1)) ?

The derivative of (x^2+1/(x-1)) is (x^2-2x-1)/((x-1)^2)

What is the first derivative of (x^2+1/(x-1)) ?

The first derivative of (x^2+1/(x-1)) is (x^2-2x-1)/((x-1)^2)

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\frac{d}{d x} (\frac{x ^{2} + 1}{x - 1})

\frac{x ^{2} - 2 x - 1}{( x - 1 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{x ^{2} + 1}{x - 1})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( x ^{2} + 1 ) ( x - 1 ) - \frac{d}{d x} ( x - 1 ) ( x ^{2} + 1 )}{( x - 1 ) ^{2}}

\frac{d}{d x} (x^{2} + 1) = 2 x

\frac{d}{d x} (x - 1) = 1

= \frac{2 x ( x - 1 ) - 1 \cdot ( x ^{2} + 1 )}{( x - 1 ) ^{2}}

Simplify

\frac{2 x ( x - 1 ) - 1 \cdot ( x ^{2} + 1 )}{( x - 1 ) ^{2}} : \frac{x ^{2} - 2 x - 1}{( x - 1 ) ^{2}}

= \frac{x ^{2} - 2 x - 1}{( x - 1 ) ^{2}}

t^{2} y^{^{''}} + 2 t y^{^{'}} - 6 y = 0

\int \frac{1}{3 + t} d t

y^{^{'}} = 3 y x^{2} - 3 x^{2}

x \to - 3 lim (\frac{2}{x ^{2}})

\int - 64 (1 + 4 t)^{- 3} d t

What is the derivative of (x^2+1/(x-1)) ?
The derivative of (x^2+1/(x-1)) is (x^2-2x-1)/((x-1)^2)
What is the first derivative of (x^2+1/(x-1)) ?
The first derivative of (x^2+1/(x-1)) is (x^2-2x-1)/((x-1)^2)