Solution
Solution
Solution steps
Apply Series Ratio Test:diverges
Popular Examples
sum from n=1 to infinity of 2(0.1)^{n-1}sum from n=1 to infinity of 3/((2n+5)^3)sum from n=1 to infinity of (3n)/(n^2-7)sum from n=1 to infinity of 2e^{-2n}sum from n=0 to infinity of 1/(1-4n)
Frequently Asked Questions (FAQ)
What is the sum from n=1 to infinity of 4^{n-1} ?
The sum from n=1 to infinity of 4^{n-1} is diverges