What is the integral from 2 to 3 of (5x^{-1}) ?

The integral from 2 to 3 of (5x^{-1}) is 5(ln(3)-ln(2))

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integral from 2 to 3 of (5x^{-1})

\int_{2}^{3} (5 x^{- 1}) d x

5 (ln (3) - ln (2))

Decimal Notation

2.02732 \dots

Solution steps

\int_{2}^{3} 5 x^{- 1} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 5 \cdot \int_{2}^{3} x^{- 1} d x

Use the common integral:

\int x^{- 1} d x = ln (∣ x ∣)

= 5 [ln ∣ x ∣]_{2}^{3}

Compute the boundaries:

ln (3) - ln (2)

= 5 (ln (3) - ln (2))

x y^{^{'}} + y = 4 x y^{2}

\frac{d}{d x} (\frac{x}{x ^{- 1} + 13})

2^{50}

\frac{d ^{2}}{d x ^{2}} (\frac{1}{x ^{2}})

\int 3 x^{2} (x^{3} + 1)^{10} d x

What is the integral from 2 to 3 of (5x^{-1}) ?
The integral from 2 to 3 of (5x^{-1}) is 5(ln(3)-ln(2))