What is the sum from n=1 to infinity of (ln(5n))/n ?

The sum from n=1 to infinity of (ln(5n))/n is diverges

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sum from n=1 to infinity of (ln(5n))/n

n = 1 \sum \infty \frac{ln ( 5 n )}{n}

diverges

Solution steps

n = 1 \sum \infty \frac{ln ( 5 n )}{n}

Apply Series Integral Test:

diverges

= diverges

k = 2 \sum \infty \frac{1}{k ^{2} - k}

k = 1 \sum \infty \frac{1}{2 ^{k} + k}

k = 3 \sum \infty \frac{1}{k ^{2} - k}

n = 1 \sum \infty n \cdot (\frac{1}{3})^{n}

n = 1 \sum \infty (- 1)^{2 n} \frac{1}{n}

What is the sum from n=1 to infinity of (ln(5n))/n ?
The sum from n=1 to infinity of (ln(5n))/n is diverges