What is the sum from n=0 to infinity of (3^n)/(e^n) ?

The sum from n=0 to infinity of (3^n)/(e^n) is diverges

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sum from n=0 to infinity of (3^n)/(e^n)

n = 0 \sum \infty \frac{3 ^{n}}{e ^{n}}

diverges

Solution steps

n = 0 \sum \infty \frac{3 ^{n}}{e ^{n}}

Apply Series Ratio Test:

diverges

= diverges

n = 1 \sum \infty 3 n^{- 1}

k = 2 \sum \infty (- 0.75)^{k}

n = 1 \sum \infty n^{- 0.3}

n = 1 \sum \infty \frac{sin ( nπ )}{n}

x = 0 \sum \infty \frac{x}{2 ^{x}}

What is the sum from n=0 to infinity of (3^n)/(e^n) ?
The sum from n=0 to infinity of (3^n)/(e^n) is diverges