What is the sum from n=0 to infinity of 1/n+1/(n+1) ?

The sum from n=0 to infinity of 1/n+1/(n+1) is diverges

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sum from n=0 to infinity of 1/n+1/(n+1)

n = 0 \sum \infty \frac{1}{n} + \frac{1}{n + 1}

diverges

Solution steps

n = 1 \sum \infty \frac{1}{n} + \frac{1}{n + 1}

Apply Series Comparison Test:

diverges

= diverges

j = 1 \sum \infty 5^{- 3 j}

n = 0 \sum \infty \frac{1}{n ^{8}}

n = 1 \sum \infty sin^{n} (1)

n = 1 \sum \infty \frac{n ^{6}}{n !}

n = 1 \sum \infty (\frac{2}{4})^{n - 1}

What is the sum from n=0 to infinity of 1/n+1/(n+1) ?
The sum from n=0 to infinity of 1/n+1/(n+1) is diverges