What is the sum from n=0 to infinity of (1/21)^n ?

The sum from n=0 to infinity of (1/21)^n is 21/20

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sum from n=0 to infinity of (1/21)^n

n = 0 \sum \infty (\frac{1}{21})^{n}

\frac{21}{20}

Solution steps

n = 0 \sum \infty (\frac{1}{21})^{n}

Apply Series Geometric Test:

\frac{21}{20}

= \frac{21}{20}

n = 2 \sum \infty n^{l n (n)}

n = 1 \sum \infty \frac{8}{9 ^{n}}

n = 1 \sum \infty \frac{1}{n + 7}

n = 1 \sum \infty \frac{5}{n ^{2} + n}

n = 0 \sum \infty \frac{2}{n} - \frac{2}{n + 1}

What is the sum from n=0 to infinity of (1/21)^n ?
The sum from n=0 to infinity of (1/21)^n is 21/20