What is maclaurin 1/(x^2+x+1) ?

The answer to maclaurin 1/(x^2+x+1) is 1-x+x^3-x^4+x^6+\ldots

Popular >

maclaurin 1/(x^2+x+1)

maclaurin

\frac{1}{x ^{2} + x + 1}

1 - x + x^{3} - x^{4} + x^{6} + \dots

Solution steps

Apply the Maclaurin Formula

= 1 + \frac{\frac{d}{d x} ( \frac{1}{x ^{2} + x + 1} ) ( 0 )}{1 !} x + \frac{\frac{d ^{2}}{d x ^{2}} ( \frac{1}{x ^{2} + x + 1} ) ( 0 )}{2 !} x^{2} + \frac{\frac{d ^{3}}{d x ^{3}} ( \frac{1}{x ^{2} + x + 1} ) ( 0 )}{3 !} x^{3} + \dots

Evaluate Derivatives

= 1 + \frac{- 1}{1 !} x + \frac{0}{2 !} x^{2} + \frac{6}{3 !} x^{3} + \frac{- 24}{4 !} x^{4} + \frac{0}{5 !} x^{5} + \frac{720}{6 !} x^{6} + \dots

Refine

= 1 - x + x^{3} - x^{4} + x^{6} + \dots

x \to 3 lim (5 x^{3} - 3 x^{2} + x - 6)

\int e^{r t} d t

\int 2 x e^{x^{2} + y^{2}} d x

x \to 2 + lim (\frac{1}{x - 2} - \frac{1}{x - 2})

\int \frac{1}{u ( 1 - u )} d u

What is maclaurin 1/(x^2+x+1) ?
The answer to maclaurin 1/(x^2+x+1) is 1-x+x^3-x^4+x^6+\ldots