What is the sum from n=15 to infinity of (2/3)^n ?

The sum from n=15 to infinity of (2/3)^n is converges

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sum from n=15 to infinity of (2/3)^n

n = 15 \sum \infty (\frac{2}{3})^{n}

converges

Solution steps

n = 15 \sum \infty (\frac{2}{3})^{n}

Apply Series Ratio Test:

converges

= converges

n = 2 \sum \infty \frac{1}{2 n}

n = 1 \sum \infty 12 sin^{n} (7 0^{\circ})

n = 0 \sum \infty \frac{n}{5 n ^{2} + 1}

n = 1 \sum \infty \frac{n}{n ^{3} + n + 1}

n = 0 \sum \infty (\frac{4 π}{e})^{n}

What is the sum from n=15 to infinity of (2/3)^n ?
The sum from n=15 to infinity of (2/3)^n is converges