Solution

Solution

Solution steps
Apply the constant multiplication rule:
Apply Series Divergence Test:diverges

Popular Examples

sum from n=1 to infinity of (1+6/n)^nsum from n=0 to infinity of (n^2)/(2n)sum from n=5 to infinity of (1^n)/(n!)sum from n=1 to infinity of (-1^n)/(e^n)sum from n=1 to infinity of (6/9)^{n-1}

Frequently Asked Questions (FAQ)

  • What is the sum from n=0 to infinity of 10ln(8-n) ?

    The sum from n=0 to infinity of 10ln(8-n) is diverges