What is the sum from n=0 to infinity of | 1/n | ?

The sum from n=0 to infinity of | 1/n | is diverges

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sum from n=0 to infinity of | 1/n |

n = 0 \sum \infty \frac{1}{n}

diverges

Solution steps

n = 1 \sum \infty \frac{1}{n}

Simplify

\frac{1}{n} : \frac{1}{∣ n ∣}

= n = 1 \sum \infty \frac{1}{∣ n ∣}

Apply Series Limit Comparison Test:

diverges

= diverges

n = 0 \sum \infty (\frac{4}{11})^{n}

j = 1 \sum \infty 2 (- \frac{3}{5})^{j}

n = 1 \sum \infty - \frac{1}{1 0 ^{n}}

n = 1 \sum \infty 4 (\frac{π}{4})^{n}

n = 1 \sum \infty n! e^{- 2 n}

What is the sum from n=0 to infinity of | 1/n | ?
The sum from n=0 to infinity of | 1/n | is diverges