Solution

Solution

Solution steps
Apply Series Ratio Test:diverges

Popular Examples

sum from n=1 to infinity of 3(2/5)^nsum from n=1 to infinity of (ln(n^4))/nsum from n=2 to infinity of 5/(n(n+2))sum from n=1 to infinity of 1/(3^n-n)sum from k=1 to infinity} 1/(sqrt(k) of-1/(\sqrt{k+2))

Frequently Asked Questions (FAQ)

  • What is the sum from n=1 to infinity of (n/e)^n ?

    The sum from n=1 to infinity of (n/e)^n is diverges