What is (\partial}{\partial u}(\frac{u-v)/2) ?

The answer to (\partial}{\partial u}(\frac{u-v)/2) is 1/2

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(\partial}{\partial u}(\frac{u-v)/2)

\frac{\partial}{\partial u} (\frac{u - v}{2})

\frac{1}{2}

Solution steps

\frac{\partial}{\partial u} (\frac{u - v}{2})

Treat

v

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{2} \frac{\partial}{\partial u} (u - v)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{1}{2} (\frac{\partial}{\partial u} (u) - \frac{\partial}{\partial u} (v))

\frac{\partial}{\partial u} (u) = 1

\frac{\partial}{\partial u} (v) = 0

= \frac{1}{2} (1 - 0)

Simplify

= \frac{1}{2}

\frac{\partial}{\partial x} (5 x + y)

\int \frac{7 x ^{2}}{1 - x ^{6}} d x

\frac{d}{d y} (y z)

x \to 2 lim (- x^{2} + 3)

\frac{d}{d x} (2 + \frac{( - 1 ) ^{x}}{x})

What is (\partial}{\partial u}(\frac{u-v)/2) ?
The answer to (\partial}{\partial u}(\frac{u-v)/2) is 1/2