What is the sum from n=1 to infinity of ln(n-1) ?

The sum from n=1 to infinity of ln(n-1) is diverges

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sum from n=1 to infinity of ln(n-1)

n = 1 \sum \infty ln (n - 1)

diverges

Solution steps

n = 2 \sum \infty ln (n - 1)

Apply Series Divergence Test:

diverges

= diverges

n = 1 \sum \infty \frac{( - 5 ) ^{n}}{4}

k = 0 \sum \infty (0.1)^{k}

n = 0 \sum \infty \frac{2}{7 - 3 n}

n = 0 \sum \infty \frac{n}{n}

n = 0 \sum \infty (1 - i)^{n}

What is the sum from n=1 to infinity of ln(n-1) ?
The sum from n=1 to infinity of ln(n-1) is diverges