What is the sum from n=0 to infinity of 4+5/(n^3) ?

The sum from n=0 to infinity of 4+5/(n^3) is diverges

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sum from n=0 to infinity of 4+5/(n^3)

n = 0 \sum \infty 4 + \frac{5}{n ^{3}}

diverges

Solution steps

n = 1 \sum \infty 4 + \frac{5}{n ^{3}}

Apply Series Divergence Test:

diverges

= diverges

n = 1 \sum \infty \frac{1}{4 n ^{2} - 49}

n = 1 \sum \infty 6 n^{2} e^{- n^{3}}

n = 1 \sum \infty \frac{1}{n ^{\frac{5}{4}}}

n = 1 \sum \infty \frac{7}{n} - \frac{7}{n ^{2}}

n = 1 \sum \infty n e^{- 5 n^{2}}

What is the sum from n=0 to infinity of 4+5/(n^3) ?
The sum from n=0 to infinity of 4+5/(n^3) is diverges