What is the solution for (x^2+1)(dy)/(dx)+2xy=4x^2 ?

The solution for (x^2+1)(dy)/(dx)+2xy=4x^2 is y=(4x^3)/(3(x^2+1))+(c_{1})/(x^2+1)

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(x^2+1)(dy)/(dx)+2xy=4x^2

(x^{2} + 1) \frac{d y}{d x} + 2 x y = 4 x^{2}

y = \frac{4 x ^{3}}{3 ( x ^{2} + 1 )} + \frac{c _{1}}{x ^{2} + 1}

Solution steps

(x^{2} + 1) \frac{d y}{d x} + 2 x y = 4 x^{2}

Solve linear ODE:

y = \frac{4 x ^{3}}{3 ( x ^{2} + 1 )} + \frac{c _{1}}{x ^{2} + 1}

y = \frac{4 x ^{3}}{3 ( x ^{2} + 1 )} + \frac{c _{1}}{x ^{2} + 1}

\int 10 sin^{2} (x co) s^{2} x d x

\frac{d}{d x} (k x^{4} (x_{0} - x))

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\int_{1}^{5} \frac{x - 1}{x ^{3} + x} d x

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What is the solution for (x^2+1)(dy)/(dx)+2xy=4x^2 ?
The solution for (x^2+1)(dy)/(dx)+2xy=4x^2 is y=(4x^3)/(3(x^2+1))+(c_{1})/(x^2+1)