What is the sum from n=1 to infinity of (2^n)/(2n-1) ?

The sum from n=1 to infinity of (2^n)/(2n-1) is diverges

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sum from n=1 to infinity of (2^n)/(2n-1)

n = 1 \sum \infty \frac{2 ^{n}}{2 n - 1}

diverges

Solution steps

n = 1 \sum \infty \frac{2 ^{n}}{2 n - 1}

Apply Series Ratio Test:

diverges

= diverges

n = 1 \sum \infty cos (6)

n = 1 \sum \infty \frac{n}{5 n ^{2} - 4}

n = 0 \sum \infty tanh (n)

n = 0 \sum \infty 8

n = 2 \sum \infty (\frac{1}{4})^{3 n}

What is the sum from n=1 to infinity of (2^n)/(2n-1) ?
The sum from n=1 to infinity of (2^n)/(2n-1) is diverges