What is the sum from n=0 to infinity of 1+((-1)^n)/n ?

The sum from n=0 to infinity of 1+((-1)^n)/n is diverges

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sum from n=0 to infinity of 1+((-1)^n)/n

n = 0 \sum \infty 1 + \frac{( - 1 ) ^{n}}{n}

diverges

Solution steps

n = 1 \sum \infty 1 + \frac{( - 1 ) ^{n}}{n}

Apply Series Divergence Test:

diverges

= diverges

k = 1 \sum \infty [(k) (\frac{1}{2})^{k}]

n = 2 \sum \infty \frac{n ^{n}}{n !}

k = 1 \sum \infty \frac{2}{k ln ( 9 k )}

n = 8 \sum \infty \frac{1}{n} - \frac{1}{n + 3}

n = 3 \sum \infty (1 + n)^{- 1}

What is the sum from n=0 to infinity of 1+((-1)^n)/n ?
The sum from n=0 to infinity of 1+((-1)^n)/n is diverges