What is the tangent of x^2+y^2=29,(2,-5) ?

The tangent of x^2+y^2=29,(2,-5) is y= 2/5 x-29/5

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tangent of x^2+y^2=29,(2,-5)

tangent of

x^{2} + y^{2} = 29, (2, - 5)

y = \frac{2}{5} x - \frac{29}{5}

Solution steps

Find the slope of

x^{2} + y^{2} = 29 : \frac{d y}{d x} = - \frac{x}{y}

Compute the slope of

x^{2} + y^{2} = 29

(2, - 5) : m = \frac{2}{5}

Find the line with slope m=

\frac{2}{5}

and passing through

(2, - 5) : y = \frac{2}{5} x - \frac{29}{5}

y = \frac{2}{5} x - \frac{29}{5}

\frac{d}{d x} (3 ln (x) - 5)

\int \frac{3 x ^{2} + 2 x + 7}{x ^{2} + 1} d x

x^{3}, at x = - 5

\int \frac{1}{- 5 x} d x

What is the tangent of x^2+y^2=29,(2,-5) ?
The tangent of x^2+y^2=29,(2,-5) is y= 2/5 x-29/5