What is the sum from n=1 to infinity of (1/10)^{n-1} ?

The sum from n=1 to infinity of (1/10)^{n-1} is converges

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sum from n=1 to infinity of (1/10)^{n-1}

n = 1 \sum \infty (\frac{1}{10})^{n - 1}

converges

Solution steps

n = 1 \sum \infty (\frac{1}{10})^{n - 1}

Apply Series Ratio Test:

converges

= converges

n = 1 \sum \infty 5 (\frac{3}{7})^{n}

n = 0 \sum \infty \frac{2 n}{n ^{3} + 1}

n = 1 \sum \infty \frac{1}{24} (\frac{3}{4})^{n}

n = 0 \sum \infty A n \cdot (- 1)^{n}

k = 0 \sum \infty \frac{1}{k ^{2} + 4}

What is the sum from n=1 to infinity of (1/10)^{n-1} ?
The sum from n=1 to infinity of (1/10)^{n-1} is converges