What is the sum from n=0 to infinity of cos(n/2) ?

The sum from n=0 to infinity of cos(n/2) is diverges

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sum from n=0 to infinity of cos(n/2)

n = 0 \sum \infty cos (\frac{n}{2})

diverges

Solution steps

n = 0 \sum \infty cos (\frac{n}{2})

Apply Series Divergence Test:

diverges

= diverges

n = 0 \sum \infty (\frac{- 1}{3})^{n}

n = 0 \sum \infty \frac{8}{9 - n}

n = 0 \sum \infty \frac{- 1 ^{n}}{3 ^{n}}

n = 0 \sum \infty n^{- 9}

n = 1 \sum \infty (\frac{4}{9})^{n}

What is the sum from n=0 to infinity of cos(n/2) ?
The sum from n=0 to infinity of cos(n/2) is diverges