What is the slope ofintercept (-1,-1),(1,0) ?

The slope ofintercept (-1,-1),(1,0) is y= 1/2 x-1/2

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slope ofintercept (-1,-1),(1,0)

slope intercept

(- 1, - 1), (1, 0)

y = \frac{1}{2} x - \frac{1}{2}

Solution steps

Compute the slope

(- 1, - 1), (1, 0) : m = \frac{1}{2}

Compute the

y

intercept:

b = - \frac{1}{2}

Construct the line equation

y = mx + b

where

m = \frac{1}{2}

and

b = - \frac{1}{2}

y = \frac{1}{2} x - \frac{1}{2}

\frac{d}{d x} (2 x + x ln (x))

f (x) = sin (6 x)

\int_{0}^{1} x^{4} d x

\frac{d}{d x} (x^{3} (x^{2} + 1)^{7})

n = 1 \sum \infty \frac{80}{8 ^{n}}

What is the slope ofintercept (-1,-1),(1,0) ?
The slope ofintercept (-1,-1),(1,0) is y= 1/2 x-1/2