What is the sum from n=1 to infinity of (pi/e)^n ?

The sum from n=1 to infinity of (pi/e)^n is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sum from n=1 to infinity of (pi/e)^n

n = 1 \sum \infty (\frac{π}{e})^{n}

diverges

Solution steps

n = 1 \sum \infty (\frac{π}{e})^{n}

Apply Series Ratio Test:

diverges

= diverges

n = 1 \sum \infty \frac{1}{- n}

n = 1 \sum \infty \frac{n + 5}{n + 4}

n = 2 \sum \infty ln (\frac{n + 1}{n})

k = 1 \sum \infty \frac{3 k - 2}{3 ^{k}}

n = 1 \sum \infty \frac{1}{6 n ^{4} + 24 n}

What is the sum from n=1 to infinity of (pi/e)^n ?
The sum from n=1 to infinity of (pi/e)^n is diverges