What is the sum from n=0 to infinity of (0.03)^n ?

The sum from n=0 to infinity of (0.03)^n is 1.03092…

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sum from n=0 to infinity of (0.03)^n

n = 0 \sum \infty (0.03)^{n}

1.03092 \dots

Solution steps

n = 0 \sum \infty 0.0 3^{n}

Apply Series Geometric Test:

1.03092 \dots

= 1.03092 \dots

k = 1 \sum \infty (- \frac{6}{7})^{k}

k = 1 \sum \infty (\frac{2}{3})^{k + 2}

n = 1 \sum \infty \frac{4}{n ! + 4 ^{n}}

n = 1 \sum \infty \frac{9 n}{9 n + 1}

n = 2 \sum \infty (- 0.8)^{n}

What is the sum from n=0 to infinity of (0.03)^n ?
The sum from n=0 to infinity of (0.03)^n is 1.03092…