What is the sum from n=0 to infinity of (7/5)^n ?

The sum from n=0 to infinity of (7/5)^n is diverges

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sum from n=0 to infinity of (7/5)^n

n = 0 \sum \infty (\frac{7}{5})^{n}

diverges

Solution steps

n = 0 \sum \infty (\frac{7}{5})^{n}

Apply Series Geometric Test:

diverges

= diverges

n = 0 \sum \infty \frac{sin ( \frac{1}{n} )}{n}

n = 0 \sum \infty 3 + 15 + 75 + 375

n = 1 \sum \infty \frac{5}{2 ^{n - 2}}

n = 1 \sum \infty \frac{1}{( n + 2 ) ^{3}}

k = 0 \sum \infty \frac{1}{100 + k}

What is the sum from n=0 to infinity of (7/5)^n ?
The sum from n=0 to infinity of (7/5)^n is diverges