What is the sum from n=0 to infinity of (14)/(14+n) ?

The sum from n=0 to infinity of (14)/(14+n) is diverges

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sum from n=0 to infinity of (14)/(14+n)

n = 0 \sum \infty \frac{14}{14 + n}

diverges

Solution steps

n = 0 \sum \infty \frac{14}{14 + n}

Apply the constant multiplication rule:

\sum c \cdot a_{n} = c \cdot \sum a_{n}

= 14 \cdot n = 0 \sum \infty \frac{1}{14 + n}

Apply Series Integral Test:

diverges

= 14 diverges

= diverges

k = 0 \sum \infty (- \frac{5}{8})^{k}

n = 1 \sum \infty \frac{1 - n}{n ^{2}}

n = 0 \sum \infty - ln (3 - n)

n = 1 \sum \infty (0.6)^{n}

k = 0 \sum \infty \frac{k}{8 k + 1}

What is the sum from n=0 to infinity of (14)/(14+n) ?
The sum from n=0 to infinity of (14)/(14+n) is diverges