What is derivative of f(x)= 1/(t^2) ?

The answer to derivative of f(x)= 1/(t^2) is (dt)/(dx)=0

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derivative of f(x)= 1/(t^2)

derivative of

f (x) = \frac{1}{t ^{2}}

\frac{d t}{d x} = 0

Solution steps

f (x) = \frac{1}{t ^{2}}

Treat

t

t (x)

Differentiate both sides:

0 = - \frac{2 \frac{d t}{d x}}{t ^{3}}

Isolate

\frac{d t}{d x} : \frac{d t}{d x} = 0

\frac{d t}{d x} = 0

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y = - x^{2} + 6 x, y = x^{2} - 4 x

\frac{4}{( 11 x - 3 ) ^{9}}

\int_{0}^{\frac{π}{2}} cos (x) d x

\int \frac{x ^{2}}{100 + x ^{2}} d x

What is derivative of f(x)= 1/(t^2) ?
The answer to derivative of f(x)= 1/(t^2) is (dt)/(dx)=0