What is the sum from n=0 to infinity of (1/22)^n ?

The sum from n=0 to infinity of (1/22)^n is 22/21

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sum from n=0 to infinity of (1/22)^n

n = 0 \sum \infty (\frac{1}{22})^{n}

\frac{22}{21}

Solution steps

n = 0 \sum \infty (\frac{1}{22})^{n}

Apply Series Geometric Test:

\frac{22}{21}

= \frac{22}{21}

n = 0 \sum \infty 5 (\frac{9}{10})^{n}

n = 0 \sum \infty (\frac{3}{n})^{\frac{1}{n}}

n = 2 \sum \infty \frac{n ^{4}}{n ^{3}}

n = 2 \sum \infty n e^{- 5 n}

n = 0 \sum \infty e^{3 n}

What is the sum from n=0 to infinity of (1/22)^n ?
The sum from n=0 to infinity of (1/22)^n is 22/21