What is the sum from k=1 to infinity of 4/k+8^{-k} ?

The sum from k=1 to infinity of 4/k+8^{-k} is diverges

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sum from k=1 to infinity of 4/k+8^{-k}

k = 1 \sum \infty \frac{4}{k} + 8^{- k}

diverges

Solution steps

k = 1 \sum \infty \frac{4}{k} + 8^{- k}

Apply Series Comparison Test:

diverges

= diverges

n = 0 \sum \infty \frac{e ^{\frac{1}{n}}}{n}

k = 4 \sum \infty \frac{1}{k ^{2} - k}

n = 1 \sum \infty \frac{e ^{n}}{4 ^{n}}

n = 1 \sum \infty \frac{n ^{2}}{n}

x = 2 \sum \infty \frac{1}{x ln ( x )}

What is the sum from k=1 to infinity of 4/k+8^{-k} ?
The sum from k=1 to infinity of 4/k+8^{-k} is diverges