What is the sum from k=1 to infinity of (k^k)/(2^k) ?

The sum from k=1 to infinity of (k^k)/(2^k) is diverges

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sum from k=1 to infinity of (k^k)/(2^k)

k = 1 \sum \infty \frac{k ^{k}}{2 ^{k}}

diverges

Solution steps

k = 1 \sum \infty \frac{k ^{k}}{2 ^{k}}

Apply Series Root Test:

diverges

= diverges

i = 1 \sum \infty 3 e^{i}

n = 1 \sum \infty - \frac{1}{1 8 ^{n}}

n = 1 \sum \infty (cos (14))^{n}

n = 1 \sum \infty \frac{- 1 ^{n - 1}}{n}

n = 2 \sum \infty \frac{n}{n ^{2} - 2}

What is the sum from k=1 to infinity of (k^k)/(2^k) ?
The sum from k=1 to infinity of (k^k)/(2^k) is diverges