What is the sum from n=0 to infinity of (4^n)/(2^n) ?

The sum from n=0 to infinity of (4^n)/(2^n) is diverges

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sum from n=0 to infinity of (4^n)/(2^n)

n = 0 \sum \infty \frac{4 ^{n}}{2 ^{n}}

diverges

Solution steps

n = 0 \sum \infty \frac{4 ^{n}}{2 ^{n}}

Apply Series Ratio Test:

diverges

= diverges

n = 2 \sum \infty \frac{7}{n ( n + 2 )}

n = 1 \sum \infty \frac{n + 2}{n ^{2}}

n = 1 \sum \infty \frac{1}{( n + 1 ) n}

n = 1 \sum \infty sin (9)

n = 1 \sum \infty \frac{2}{7 ^{n}}

What is the sum from n=0 to infinity of (4^n)/(2^n) ?
The sum from n=0 to infinity of (4^n)/(2^n) is diverges