What is the derivative of 1+1/(3x) ?

The derivative of 1+1/(3x) is -1/(3x^2)

What is the first derivative of 1+1/(3x) ?

The first derivative of 1+1/(3x) is -1/(3x^2)

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\frac{d}{d x} (1 + \frac{1}{3 x})

- \frac{1}{3 x ^{2}}

Solution steps

\frac{d}{d x} (1 + \frac{1}{3 x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) + \frac{d}{d x} (\frac{1}{3 x})

\frac{d}{d x} (1) = 0

\frac{d}{d x} (\frac{1}{3 x}) = - \frac{1}{3 x ^{2}}

= 0 - \frac{1}{3 x ^{2}}

Simplify

= - \frac{1}{3 x ^{2}}

\int \frac{1}{sin ( 3 x )} d x

\int_{- 2}^{2} 3

(\frac{1}{x ^{2} - 1})^{^{'}}

f (x) = 4 - 3 x^{2}, (5, - 71)

\frac{- 0.5}{s ^{2} + s + 1}

What is the derivative of 1+1/(3x) ?
The derivative of 1+1/(3x) is -1/(3x^2)
What is the first derivative of 1+1/(3x) ?
The first derivative of 1+1/(3x) is -1/(3x^2)