What is the sum from n=4 to infinity of ln(1+1/n) ?

The sum from n=4 to infinity of ln(1+1/n) is diverges

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sum from n=4 to infinity of ln(1+1/n)

n = 4 \sum \infty ln (1 + \frac{1}{n})

diverges

Solution steps

n = 4 \sum \infty ln (1 + \frac{1}{n})

Apply Series Limit Comparison Test:

diverges

= diverges

n = 2 \sum \infty \frac{7}{3 ^{n}}

n = 2 \sum \infty 2^{- 4 n}

n = 0 \sum \infty \frac{n}{6 + n ^{4}}

n = 1 \sum \infty n^{5} e^{n^{6}}

n = 5 \sum \infty n^{- s i n (3)}

What is the sum from n=4 to infinity of ln(1+1/n) ?
The sum from n=4 to infinity of ln(1+1/n) is diverges