What is the sum from n=1 to infinity of (cos(20))^n ?

The sum from n=1 to infinity of (cos(20))^n is converges

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sum from n=1 to infinity of (cos(20))^n

n = 1 \sum \infty (cos (20))^{n}

converges

Solution steps

n = 1 \sum \infty (cos (20))^{n}

n = k \sum \infty (a_{n}) = n = 0 \sum \infty (a_{n}) - a_{0} - a_{1} - \dots a_{k - 1}

= n = 0 \sum \infty (cos (20))^{n} - (cos (20))^{0}

n = 0 \sum \infty (cos (20))^{n} =

converges

= converges - (cos (20))^{0}

= converges

x = 1 \sum \infty \frac{x}{e ^{x}}

k = 0 \sum \infty (\frac{5}{6})^{k}

n = 1 \sum \infty \frac{1 + n}{n ^{2}}

n = 6 \sum \infty \frac{1}{( n - 3 ) ^{4}}

n = 1 \sum \infty \frac{1}{n ^{7} + 8}

What is the sum from n=1 to infinity of (cos(20))^n ?
The sum from n=1 to infinity of (cos(20))^n is converges